6 comments:

  1. Arpit JainJune 22, 2018 at 2:56 PM

    This comment has been removed by the author.

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  2. UnknownJune 22, 2018 at 4:07 PM

    ";

    if($N%2==0)
    {
    echo "The given number is even";
    echo "
    ";
    }

    else
    {
    echo "The given number is odd";
    echo "
    ";
    }

    ?>

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  3. UnknownJune 22, 2018 at 5:10 PM

    php
    $num=$_POST['n1'];
    if($num%2==0)
    echo"the number $num is even";
    else
    echo"the number $num is odd";

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  4. Arpit JainJune 28, 2018 at 8:11 AM

    $check=$_GET["num"];
    if($check%2==0)
    echo "even";
    else
    echo "odd";

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  5. UnknownJuly 10, 2018 at 11:17 PM

    $N=$_POST['n'];

    echo "The no. to be checked is :".$N;
    echo "
    ";

    if($N%2==0)
    {
    echo "The given number is even";
    echo "
    ";
    }

    else
    {
    echo "The given number is odd";
    echo "
    ";
    }

    ReplyDelete
  6. UnknownJuly 14, 2018 at 2:28 PM

    ?php
    $num1=$_POST["num"];
    if($num1%2==0)
    {echo"$num1"."even";
    }else
    {echo"$num1"."odd";}
    ?>

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